Study Anytime Any Where We Will Open The Knowledge For You Anish Sir 24x7 Learning solution It Is Time to join JOB
23 October 2017

Study Anytime Any Where

23 October 2017

We Will Open The Knowledge For You

23 October 2017

Anish Sir 24x7 Learning solution

23 October 2017

It Is Time to join JOB

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Anish Sir

Anish Sir

"I am delighted once again to pen the welcome note to the Tosh!Yas Technologies ."

 Call +91 74 88 34 7779  | Email : anishsingh@live.com

Website URL: http://toshiyas.in
Thursday, 21 September 2017 05:56

C -for-Program

Print the first five numbers starting from I together with their squares.

#include<stdio.h>

#include<conio.h>

Void main ( )

{

       Int  I;

       Clrscr ( );

       For (i=l; <=5; i++)

       Printf (“\n  Number:  %5d  it’ s  Square:  %5d”, I, i*i);

      getch();

}

OUTPUT:

Number:  1  it’ s  Square:  1

Number:  2  it’ s  Square:  4

Number:  3  it’ s  Square:  9

Number:  4  it’ s  Square:  16

Number:  5  it’ s  Square:  25      

#include<stdio.h>

#include<conio.h>

Valid main ( )

{

        Int  I;

        Clrscr ( ) ;

        For ( i=l; i<=15; i= i+l)

        Printf (“%5d”,i);

        getche ( );

}

OUTPUT:

1 2 3 4 5 6 7 8 9 10 11 12 13 14  15

Write a program to display even numbers from 0 to 14.  Declare the initial counter value before the for loop statement.

#include<stdio.h>

#include<conio.h>

Void main ( )

{

        Int  i=o ;

        Clrscr ( );

        For (i<=15;)

        {

                  Printf (“% 5 d “ , i) ;

                  i+=2;

        }

}

OUTPUT:

O 2 4 6 7 8 10 12 14

Write a program to count numbers between 1 to 100 not divisible by 2, 3, and 5.

#include<stdio.h>

#include<conio.h>

Void main ( )

{

     Int  x, c=0;

     Clrscr ( );

     Printf (“\n  Numbers  from  1  to  100  not  divisible  by  2, 3  &  5 \n \n”);

     For (x=0  ;x<=100 ;x ++)

     {

            If (x%2 !=0   &&  x%3!=0  && x%5!=0)

            {

                Printf (%”%d\t” ,x),

                C++;

            }

     }

     Printf (“\nTotal numbers  :  %d”, c );

}

OUTPUT:

Numbers  from  1  to  100  not  divisible  by 2, 3  &  5

1    7    11    13    17    19    23    29    31    37     37

41   43    47    49    53     59    61    67    71     73

77    79    83    89   91    97

Total  Numbers  :  26

Write a program to display the numbers in increasing and decreasing order using the infinite for loop.    

#include<stdio.h>

#include<conio.h>           

Void main ( )

{

       Int  n, a, b;

       Clrscr ( );

       Printf (“Enter  a  number  :”);

       Scanf (“, &);

       A=b=n;

       Printf (“ (++)  ( - - ) \n”);

       Printf (“============”);

       For (;  ;  (a++, b - - ) )

       {

             Printf (“\n%d\t%d”, a, b);

             If (b==0)

             Break;

       }

}

OUTPUT:

Enter  a  number  :  5

(++)         ( - - )

===========

5    5

6    4

7    3

8    2

9    1

10  0   

create an infinite for loop.  Check each value of the for loop.  If the value is even display it otherwise continue with iterations.  Print Even numbers from 1 to 21.  Use break statement to terminate the program.

#include<stdio.h>

#include<conio.h>

Void main ( )

{

       Int  i=l;

       Clrscr ( );

       Printf (“\n \t \t  Table  of  Even  numbers  from  1  to  20”);

       Printf (“\n \t \t  ===== == ==== ======= ==== = == == \n”);

       For (;  ;)

       {

           If (i==21)

           Break;

           else  if (i%2==0)

           {

                 Printf (“%d\t”, i);

                 I++;

                 Continue;

           }

           else

           {

                I++;

                Continue;

           }

    }

    getche ( );

}

OUTPUT:

Table  of  Even  numbers  from  1  to  20

====  ==  ====  =======  ===  =  ==  ==

2  4  6  8  10  12  14  16  18  20   

Calculate the sum of the first five numbers and their squares. Display their results.

Void main ( )

{

        Int  I,  sum=0, sqsum=0;

        Clrscr ( );

        For (i=l; i<-5; ++)

        {

               Sum+-I;

               Sqsum+=i*I;

               Printf (“\n  number:  %5d  it’ s  Square  :  %8d”, I, i*i);

       }

       Printf (“\n===================================”);

       Printf (“\n  The  sum  of  the  five  numbers (1  t0  5)  : -%6d”, sum);

       Printf (“\n  The  sum  of  their  Squares: -%9d”,  sqsum);

       getche ( );

}

OUTPUT:

Number:             1                 it’ s  Square:             1

Number:             2                 it’ s  Square:             4

Number:             3                 it’ s  Square:             9

Number:             4                 it’ s  Square:            16

Number:             5                 it’ s  Square:            25

=========================================

The  sum  of  the  five  numbers (1  t0  5) : -  15

The  sum  of  their  Squares: -  55       

 Write a program to find the number in between 7 and 100 which is exactly divisible by 4 and

If divided by 5 and 6 remainders obtained should be 4.

#include<stdio.h>

#include<conio.h>

#  include  <process . h>

Void main ( )

{

       Int  x;

       Clrscr ( );

       For (x=7;x<100;x++)

       {

              If (x%4==0  &&  x%5==4  &&  x%6==4)

              {

                     Printf (“\n  Number  :  %d”, x);

              }

      }

     getche ( );

}

OUTPUT:

Number  :  64   

Write a program to find the sum of the following series.

/*  1.  1+2+3+ ..n  */

/*  2.  12+22+32+..n2  */

#include<stdio.h>

#include<conio.h>

Void main ( )

{

       Int  sum=0, ssum-0, I, j;

       Clrscr ( );

       Printf (“Enter  Number  :”);

       Scanf (“%d”,  &j);

       Clrscr ( );

       Printf (“  Numbers:”);

       For (i=1; i<=j; i++)

       Printf (“%5d”, i);

       Printf (“\n \nSquares:”);

       For (i=1; i<=j; i++)

       {

            Printf (“%5d”, i*i);

            Sum=sum+I;

            Sum=ssum+i*i;

       }

       Printf (“\n \nSum  of  Numbers  from  1  to  %d  :%d”, j, sum);

       Printf (“\nSum  of  Squares  of  1  to  %d  Numbers  :%d”, j, ssum);

}

OUTPUT:

Enter  Number:  5

Numbers:  1  2  3  4  5

Squares:  1  4  9  16  25

Sum  of  Numbers  from  1  to  5:  15

Sum  of  Squares  of  1  to  5  Numbers:  55 

Write a program to find the perfect squares from 1 to 500.

#include<stdio.h>

#include<conio.h>

# include  <math . h>

Void maid ( )

{

      Int  I, count, x;

      Float  c;

      Clrscr ( );

      Printf (“\n \n”);

      Printf (“  Perfect  squares  from  1  to  500 \n”);

      For (i=1; <=500; i++)

  {

      C=sqrt (i);

       X=floor (c);  /*  For  rounding  up  floor ( )  is  used.  */

       {

              Printf (“\t%5d”, i);

              Coun ++;

      }

  }

  Printf (“\n \n  Total  Perfect  Squares  =5d\n”, conut);

  getch ( );

}

OUTPUT:

1       4      9      16      25   36   49   64   81   121   144

169   196   225    256    289   324    361    400   441

484                             

Total  Perfect  Squares  =  22

Write a program to detect the largest number out of five numbers and display it.

#include<stdio.h>

#include<conio.h>

# include<process . h>

Void main ( )

Exit (0);

{

       Int  a, b, c, e, sum=0, I;

       Clrscr ( );

       Printf (“\nEnter  Five  numbers  :”);

       Scanf (“%d  %d  %d  %d  %d”, &a, &b, &c, &d, &e);

       For (i=sum;  i<=sum; I - -)

       {

             If (i==a  ||  i==b  ||  i==c  ||  i==d  ||  i==e)

             {

                   Printf (“The  Largest  Number  :  %d”, i);

                   Exit (0);

             }

      }

}

OUTPUT:

Enter  Five  number  :  5  2  3  7  3 

The  Largest  Number  :  7        

Write a program to detect the smallest number our of five numbers and display it.

#include<stdio.h>

#include<conio.h>

Void main ( )

{

      Int  a, b, c, d, e, sum=0, I;

      Clrscr ( );

      Printf (“\nEnter  Five  numbers  :”);

      Scanf (“%d  %d  %d  %d  %d”, &a, &b, &c, &d, &e);

      Sum=a+b+c+d+e;

      For (i=l;  i<=sum; i++)

      {

            If (i==a  ||  i==b  ||  i==c  ||  i==d  ||  i==e)

            {

            Printf (“The  Smallest  Number  :  %d”, i)

            Exit (0);

            }

      }

}

OUTPUT:

Enter  Five  numbers  :  5  2  3  7  3

The Smallest  Number:  2          

Write a program to print the five entered numbers in the ascending order.

#include<stdio.h>

#include<conio.h>

Void main ( )

{

      Int  a, b, c, d, e, sum-0, I;

      Clrscr ( );

      Printf (“\nEnter  Five  numbers  :”);

      Scanf (“%d  %d  %d  %d  %d” &a, &b, &c, &d, &e);

      Printf (“\n  Numbers  in  ascending  order  :”);

      Sum=a+b+c+d+e;

      For (i=l;  i<=sum; i++)

  {

     If (i==a  ||  i==b  ||  i==c  ||  i==d  ||  i==e)

     {

             Printf (“%3d”, i);

     }

  }

}

OUTPUT:

Enter  Five  numbers  :  5  8  7  4  1

Numbers  in  ascending  order  :  1  4  5  7  8  

Perform multiplication of two integers by using the negative sign.

#include<stdio.h>

#include<conio.h>

Void main ( )

{

      Int  a, b, c, d=0;

      Clrscr ( );

      Printf (“\n  Enter  two  numbers  :”);

      Scanf (“%d  %d”,  &a, &b);

      For (c=l; c<-b; c++)

      D= (d) – ( - a);

      Printf (“Multiplication  of  %d  *  %d  :%d”, a, b, d);

      getche ( );

}

OUTPUT:

Enter  two  numbers  :  5  5

Multiplication  of  5  *  5  :  25   

 Calculate the sum and average of five subjects.

#include<stdio.h>

#include<conio.h>

Void main ( )

{

      Int  a, b, c, d, e, sum=0, I;

      Float  avg;

      Clrscr ( );

      Printf (“\nEnter  The  Marks  of  Five  Subjects”);

      For (i=l; i<=5; i++)

      {

           Printf (“\n [%d]  Student:”, i);

           If (scanf (“%d  %d  %d  %d  %d”, &a, &b, &c, &d, &e) ==5)

           {

                 Sum=a+b+c+d+e;

                 Avg=sum/5;

                 Printf (“\n  Total  Marks  of  Student [%d]  %d”, I, sum);

                 Printf (“\n  Average  Marks  of  Student [%d]  %f\n”, I, avg);

           }

           else

           {

                Clrscr ( );

                Printf (“\n  Type  Mismatcch”);

           }

     }

}

OUTPUT:

Enter  The  Marks  of  Five  Subjects

[1] Student:  58  52  52  56  78

      Total  Marks  of  Student [1]  296

      Average  Marks  of  Student [1]  59.000000

[2] Student:             

Write a program to find perfect cubes up to a given number.

/* 1, 8, 27, 64 are perfect cubes of 1, 2, 3 and 4 */.

#include<stdio.h>

#include<conio.h>

#  include<math . h>

Void main ( )

{

      Int  I,  j,  k;

      Clrscr ( );

      Printf (“Enter  a  Number  :”);

      Scanf (“%d”, &k);

      For (i=l; i<k; i++)

      {

            For (j=l; j<=I; j++)

            {

                 If (i==pow (j,3) )

                 Printf (“\nNumber  :  %d  &   it’ s  Cube  :%d:, j, i);

            }

     }

}

OUTPUT:

Enter  a  Number  :  100

Number  :  1  &  it’ s  Cube  :  1

Number  :  2  &  it’ s  Cube  :  8

Number  :  3  &  it’ s  Cube  :  27

Number  :  4  &  it’ s  Cube  :  64

Write a program to display the stars as shown below.

*

*  *

*  *  *

*  *  *  *

*  *  *  *  *

#include<stdio.h>

#include<conio.h>

Void main ( )

{

       Int  x, I, j;

       Clrscr ( );

       Printf (“How  many  lines  stars  (*)  should  be  printed  ?  :”);

       Scanf (“%d”, &x);

       For (i=l; i<=x; i++)

       {

              For (j=l; j<=I; j++)

              {

                     Printf (“*”);

              }

              Printf (“\n”);

       }

}

OUTPUT:

How  many  lines  stars  (*)  should  be  printed  ?  :  5

*

*  *

*  *  *

*  *  *  *

*  *  *  *  *

Write a program to generate the pattern of numbers as given under.

6  5  4  3  2  1  0 

5  4  3  2  1  0

4  3  2  1  0

3  2  1  0 

2  1  0 

1  0 

0

#include<stdio.h>

#include<conio.h>

Void main ( )

{

      Int  I, c=0;

      Clrscr ( );

      Printf (“Enter  a  Number  :”);

      Scanf (“%d, &i);

      For (;i>=0i - -)

      {

            C=I;

            Printf (“\n”);

            For (;  ;)

            {

                   Printf (“%3d”, c);

                   If (c==0)

                   Break;

                   C- -;

            }

      }

}

OUTPUT:

Enter  a  number:  6

6  5  4  3  2  1  0 

5  4  3  2  1  0

4  3  2  1  0

3  2  1  0 

2  1  0 

1  0 

Write a program to display the series of numbers as given below.

1

1  2

1  2  3

1  2  3  4 

4  3  2  1

3  2  1

2  1 

1

#include<stdio.h>

#include<conio.h>

Void main ( )

{

      Int  I, j, x; 

      Printf (“\nEnter  Value  of  x  :”);

      Scanf (“%d”,&x);

      Clrscr ( );

      For (j=l; j<=x; j++)

      {

             For (i=l; i<=j; i++)

             Printf (“%3d”, i);

             Printf (“\n”);

     }

     Printf (“\n”);

     For (j=x; j>=l; I - -)

     {

            For (i=j; i>=l; I- -)

            Printf (“%3d”, i);

            Printf (“\n”);

     }

OUTPUT:

1

1  2

1  2  3

1  2  3  4 

4  3  2  1

3  2  1

2  1 

1        

Write a program to display the series of numbers as given below.

1

1  2

1  2  3

1  2  3  4 

4  3  2  1

3  2  1

2  1 

1

#include<stdio.h>

#include<conio.h>

Void main ( )

{

     Int  I, j, x;

     Printf (“\nEnter  Value  of  x  :”);

     Scanf (“%d”, &x);

     Clrscr ( );

     For (j-l; j<=x; j++)

     {

           For (i=j; i>=l; I - -)

           {

                 Printf (“%3d”, i);

           }

           Printf (“\n”);

     }

}

OUTPUT:

Enter  Value  of  x  :  4

1

1  2

1  2  3

1  2  3  4 

4  3  2  1

3  2  1

2  1 

1

Write a program to generate the pyramid structure using numerical.

#include<stdio.h>

#include<conio.h>

Void main ( )

{

      Int  k, I, j, x, p=34;

      Printf (“\n  Enter  A  number  :”);

      Scanf (“%d”, &x);

      Clrscr ( );

      For (j=0; j <=x; j++)

      {

             Gotoxy(p, j+l);

             /*  position  cursor  on  screen  (x  cordinate, y  cordinate)  */

            For (i=0 – j; I <=j; i++)

            Printf (“%3d”, abs ( I ) );

            P=p-3;

     }

}

OUTPUT:

Enter  a  number  :  3

            0

        1  0  1

    2  1  0  1  2

3  2  1  0  1  2  3    

 

Tuesday, 19 September 2017 05:11

nested loops in C

C programming allows to use one loop inside another loop. The following section shows a few examples to illustrate the concept.

Syntax

The syntax for a nested for loop statement in C is as follows −

for ( init; condition; increment ) {

   for ( init; condition; increment ) {
      statement(s);
   }
	
   statement(s);
}

The syntax for a nested while loop statement in C programming language is as follows −

while(condition) {

   while(condition) {
      statement(s);
   }
	
   statement(s);
}

The syntax for a nested do...while loop statement in C programming language is as follows −

do {

   statement(s);
	
   do {
      statement(s);
   }while( condition );

}while( condition );

A final note on loop nesting is that you can put any type of loop inside any other type of loop. For example, a 'for' loop can be inside a 'while' loop or vice versa.

Example

The following program uses a nested for loop to find the prime numbers from 2 to 100 −

#include <stdio.h>
 
int main () {

   /* local variable definition */
   int i, j;
   
   for(i = 2; i<100; i++) {

      for(j = 2; j <= (i/j); j++) 
      if(!(i%j)) break; // if factor found, not prime
      if(j > (i/j)) printf("%d is prime", i);
   }
 
   return 0;
}

When the above code is compiled and executed, it produces the following result −

2 is prime
3 is prime
5 is prime
7 is prime
11 is prime
13 is prime
17 is prime
19 is prime
23 is prime
29 is prime
31 is prime
37 is prime
41 is prime
43 is prime
47 is prime
53 is prime
59 is prime
61 is prime
67 is prime
71 is prime
73 is prime
79 is prime
83 is prime
89 is prime
97 is prime
Tuesday, 19 September 2017 05:09

do...while loop in C

Unlike for and while loops, which test the loop condition at the top of the loop, the do...while loop in C programming checks its condition at the bottom of the loop.

do...while loop is similar to a while loop, except the fact that it is guaranteed to execute at least one time.

Syntax

The syntax of a do...while loop in C programming language is −

do {
   statement(s);
} while( condition );

Notice that the conditional expression appears at the end of the loop, so the statement(s) in the loop executes once before the condition is tested.

If the condition is true, the flow of control jumps back up to do, and the statement(s) in the loop executes again. This process repeats until the given condition becomes false.

Flow Diagram

do...while loop in C

Example

#include <stdio.h>
 
int main () {

   /* local variable definition */
   int a = 10;

   /* do loop execution */
   do {
      printf("value of a: %d\n", a);
      a = a + 1;
   }while( a < 20 );
 
   return 0;
}

When the above code is compiled and executed, it produces the following result −

value of a: 10
value of a: 11
value of a: 12
value of a: 13
value of a: 14
value of a: 15
value of a: 16
value of a: 17
value of a: 18
value of a: 19
Tuesday, 19 September 2017 05:07

for loop in C

for loop is a repetition control structure that allows you to efficiently write a loop that needs to execute a specific number of times.

Syntax

The syntax of a for loop in C programming language is −

for ( init; condition; increment ) {
   statement(s);
}

Here is the flow of control in a 'for' loop −

  • The init step is executed first, and only once. This step allows you to declare and initialize any loop control variables. You are not required to put a statement here, as long as a semicolon appears.

  • Next, the condition is evaluated. If it is true, the body of the loop is executed. If it is false, the body of the loop does not execute and the flow of control jumps to the next statement just after the 'for' loop.

  • After the body of the 'for' loop executes, the flow of control jumps back up to the increment statement. This statement allows you to update any loop control variables. This statement can be left blank, as long as a semicolon appears after the condition.

  • The condition is now evaluated again. If it is true, the loop executes and the process repeats itself (body of loop, then increment step, and then again condition). After the condition becomes false, the 'for' loop terminates.

Flow Diagram

for loop in C

Example

#include <stdio.h>
 
int main () {

   int a;
	
   /* for loop execution */
   for( a = 10; a < 20; a = a + 1 ){
      printf("value of a: %d\n", a);
   }
 
   return 0;
}

When the above code is compiled and executed, it produces the following result −

value of a: 10
value of a: 11
value of a: 12
value of a: 13
value of a: 14
value of a: 15
value of a: 16
value of a: 17
value of a: 18
value of a: 19
Tuesday, 19 September 2017 04:56

while loop in C

while loop in C programming repeatedly executes a target statement as long as a given condition is true.

Syntax

The syntax of a while loop in C programming language is −

while(condition) {
   statement(s);
}

Here, statement(s) may be a single statement or a block of statements. The condition may be any expression, and true is any nonzero value. The loop iterates while the condition is true.

When the condition becomes false, the program control passes to the line immediately following the loop.

Flow Diagram

while loop in C

Here, the key point to note is that a while loop might not execute at all. When the condition is tested and the result is false, the loop body will be skipped and the first statement after the while loop will be executed.

Example

#include <stdio.h>
 
int main () {

   /* local variable definition */
   int a = 10;

   /* while loop execution */
   while( a < 20 ) {
      printf("value of a: %d\n", a);
      a++;
   }
 
   return 0;
}

When the above code is compiled and executed, it produces the following result −

value of a: 10
value of a: 11
value of a: 12
value of a: 13
value of a: 14
value of a: 15
value of a: 16
value of a: 17
value of a: 18
value of a: 19
Tuesday, 19 September 2017 04:11

C-loop

  What is a Loop?

A loop is defined as a block of statements, which are repeatedly executed for a certain number of times.

     The loops are two types.

  • Counter-controlled repetition: This is also called the definite repetition action, because the number of iterations to be performed is defined in advance in the program itself. The steps for performing counter-controlled repetitions are as follows.

Steps in Loop

Loop variable: IT is a variable used in the loop

Initialization: It is the first step in which starting and final values are assigned to the loop variable. Each time the upload value is checked by the loop itself.

Incrimination/discrimination: It is the numerical value added or subtracted to the variable in each round of the loop. The upload value is compared with the final value and if it is found less than the final value the steps in the loop are executed.  

The above steps are implemented in numerous programs in this chapter.

  • Sentinel- controlled repetition: This is also called the indefinite repetition. One cannot estimate how many    iterations are to be performed.  In this type, loop termination happens on the basis of certain conditions using the decision-making statement.

In computer programming, a loop is a sequence of instruction s that is continually repeated until a certain condition is reached. Typically, a certain process is done, such as getting an item of data and changing it, and then some condition is checked such as whether a counter has reached a prescribed number. If it hasn't, the next instruction in the sequence is an instruction to return to the first instruction in the sequence and repeat the sequence. If the condition has been reached, the next instruction "falls through" to the next sequential instruction or branches outside the loop. A loop is a fundamental programming idea that is commonly used in writing programs.

infinite loop (endless loop)

An infinite loop (sometimes called an endless loop ) is a piece of coding that lacks a functional exit so that it repeats indefinitely. In computer programming, a loop is a sequence of instruction s that is continually repeated until a certain condition is reached. Typically, a certain process is done, such as getting an item of data and changing it, and then some condition is checked, such as whether a counter has reached a prescribed number. If the presence of the specified condition cannot be ascertained, the next instruction in the sequence tells the program to return to the first instruction and repeat the sequence, which typically goes on until the program terminates automatically after a certain duration of time, or the operating system terminates the program with an error.

Usually, an infinite loop results from a programming error - for example, where the conditions for exit are incorrectly written. 

Loop Type & Description

while loop

Repeats a statement or group of statements while a given condition is true. It tests the condition before executing the loop body.

 

for loop

Executes a sequence of statements multiple times and abbreviates the code that manages the loop variable.

 

do...while loop

 It is more like a while statement, except that it tests the condition at the end of the loop body.

 

nested loops

You can use one or more loops inside any other while, for, or do..while loop.

 

Monday, 18 September 2017 06:47

C-if else Program

Write a program to check equivalence of two numbers. Use the if statement.

#include<stdio.h>

#include<conio.h>

Void main ( )

{

        Int  m, n;

        Clrscr ( );

        Printf (“\n Enter Two Numbers  :”);

        Scanf (“%d  %d”, &m, &n);

        If (m-n==0)

        Printf (“\n Two numbers are equal. “);

        getch( );

}

OUTPUT:

Enter Two Numbers  :  5  5

Two numbers are equal.

 Write a program to check whether the candidate’s age is greater than 17 or not. If yes, display

Message ‘Eligible for Voting’.

#include<stdio.h>

#include<conio.h>

Void main ( )

{

       Int  age;

       Clrscr ( );

       Printf (“\n Enter age  :”);

       Scanf (“%d, &age);

       If (age>17)

       Printf (“\n Eligible for Voting.”);

       getch ( );

}

Write a program using curly braces in the if block. Enter only the three numbers and calculate their sum and multiplication.

#include<stdio.h>

#include<conio.h>

Void main ( )                              

{

Int a, b, c, x;

       Clrscr ( );

       Printf (“\nEnter Three Numbers:”);

       X=scanf (“%d %d %d”, &a, &b, &c);

       If (x==3)

       {

           Printf (“\n Addition  :  %d”, a,+b+c);

           Printf (“\n Multiplication  :  %d”, a*b*c);

       }

}

OUTPUT:

Enter Three Numbers:  1  2  4

Addition  :  7

Multiplication  :  8

After second time execution

Enter Three Numbers:  5  v  8

Read the values of a, b and c through the keyboard. Add them and after addition check if it is In the range of 100 and 200 or not. Print the separate message for each.

#include<stdio.h>

#include<conio.h>

Void main ( )

{

       Int  a, b, c, d;

       Clrscr (“Enter Three Numbers a b c  :”);

       Printf (“%d %d %d”, &a, &b, &c);

      Printf (“a=%d b=%d c=%d”, a, b, c);

      D=a+b+c;

      If (d<=200 && d>=100)

      Printf (“\nSum is %d which is in between 100 & 200”, d);

      else

      Printf (“\nSum is %d which is out of range”, d);

      getch ( );

}

OUTPUT:    

Enter Three Numbers a b c  :  50  52  54 

A=50  b=52  c=54

Sum is 156 which is in between 100 & 200.           

Write a program to calculate the square of those numbers only whose least significant Digit is 5.

#include<stdio.h>

#include<conio.h>

Void main ( )

{

       Int  s, d;

       Clrscr ( )

       Printf (“\n Enter  a  Number  :”);

       Scanf (“%d, &s);

       D=s %10;

       If (d==5)

       {

            S=s/10;

            Printf (“\n Square  =  % d%d”, s*s++,d*d);

       }

       Else

             Printf (“\n Invalid Number”);

}

OUTPUT:

Enter  a  Number  :  25

Square  =  625 

 

Write a program to calculate the salary of medical representative based on the sales. Sales.

Bonus And incentive to be offered to him will be based on total sales.

If the sale exceeds Rs.1, 00,000,Follow the particulars of Table 1 otherwise follow Table 2.

  1. TABLE

Basic=Rs.  3000.

Hra=20% of basic.

Da=110% of basic.

Conveyance=Rs. 500.

Incentive=10% of sales.

Bonus=Rs.  500.  
  1. TABLE

Basic=Rs.  3000.

Hra=20% of basic.

Da=110% of basic.

Conveyance=Rs. 500.

Incentive=5% of sales.

Bonus=Rs.  200.  

 

#include<stdio.h>

#include<conio.h>

Void main ( )

{

        Float bs, hra, da, cv, incentive, bonus, sale, ts; 

        Clrscr ( );

        Printf (“\n Enter Total Sales in Rs.:”);

        Scanf (“%f”, &sale);

        If (sale>100000)

        {

            Bs=3000;

            Hra=20  *  bs/100;

            Da110  *  bs/100;

            Cv=500;

            Incentive=sale*10/100;

            Bonus=500;

       }

            Else

            {

                  Bs=3000;

                  Hra=20  *  bs/100;

                  Da=110  *  bs/100;

                  Cv=500;

                  Incentive=sale*5/100;

                  Bonus=200;

            }

     Ts=bs+hra+da+cv+incentive+bonus;

     Printf (“\nTotal Sales  :  % f”, sale);

     Printf (“\nBasic salary :  % f”’, bs)

     Printf (“\nHra               :  % f”, hra);

     Printf (“\nDa                 :  % f, da);

     Printf (“\nConveyance : % f”, cv);

     Printf (“\nIncentive      : % f”, incentive)

     Printf (“\nBonus            : % f”, bonus);

     Printf (“\nGross Salary : % f”, ts);

     getch ( );

}

OUTPUT:

Enter Total Sales in Rs.  100000

Total Sales:  100000.00

Basic Salary:  3000.00

Hra:  600.00

Da:  3300.00

Conveyance:  500.00

Incentive:  10000.00

Bonus:  500.00

Gross Salary:  17900.00     

Write a program to calculate energy bill. Read the starting and ending meter readings.Charges are as follows.

No. of Units    Consumed Rates in  (Rs.)

200  -  500                           3.50

100  -  200                           2.50

Less  than  100                   1.50

#include<stdio.h>

#include<conio.h>

Void main ( )

{

       Int initial, final, consumed;

       Float total;

       Clrscr ( );

       Printf (“\n Initial & Final Readings  :”);

       Scanf (“%d  %d”,  &initial,  &final);

       Consumed  =  final – initial;

       If (consumed>=200  &&  consumed<=500)

       Total=consumed  *  3.500;

       Else if (consumed>=100  &&  consumed<=199)

       Total= consumed  *  2.500;

       Else if (consumed*1.50;

       Printf (“Total bill for %d unit is %f”, consumed, total);

       getche ( );

}

OUTPUT:

Initial  &  Final Readings  :  800  850

        

Sunday, 17 September 2017 10:44

Creating a Single Group

You can create a single group in Tally.ERP 9 and configure its details as per your requirement. You can also view, alter or delete single groups that you have created.

Creating a Group

To create a single group

1.    Go to Gateway of Tally > Accounts Info. > Groups.

2.    Click the option Create under Single Group. The Group Creation screen appears.

3.    Enter the Name of the group.

4.    Enter the Alias name, if required.

5.    In the field Under, from the List of Groups displayed, select the parent group under which the group has to be classified. For example, Indirect Expenses.

Note: Groups can be created under the group Primary, if required. To classify a group under Primary, the option Allow Advanced entries in Masters should be enabled in the Master Configuration screen.

The Group Creation screen appears as shown below:

6.    Click Yes to accept the screen.

A group can be created for advanced usage, with more options to configure, by setting the option Allow Advanced Entries in Masters in F12: Configure.

Displaying a Group

To display a group

1.    Go to Gateway of Tally > Accounts Info. > Groups.

2.    Click the option Display under Single Group.

3.    Select the name of the group required from the List of Groups displayed. The ledger display screen appears as shown below:

Note: In the display mode , group details can't be modified.

Altering a Group

The details entered in a group can be modified when required.

To alter a group

1.    Go to Gateway of Tally > Accounts Info. > Groups.

2.    Click Alter under Single Group.

3.    Select the name of the group required from the List of Groups displayed.

4.    Make the necessary changes in the Group Alteration screen.

5.    Click Yes to save the changes.

Deleting a Group

Groups can be deleted from the alteration screen. Only one group can be deleted at a time.

To delete a group

1.    Go to Gateway of Tally > Accounts Info. > Groups.

2.    Click the option Alter under Single Group.

3.    Select the name of the group required from the List of Groups displayed.

4.    Click D: Delete.

5.    Click Yes to confirm deletion.

Note: A group cannot be deleted if:

         The group has sub-groups.

         The group has ledgers classified under it.

         The group is a predefined master.

Friday, 15 September 2017 09:20

Simple Calculator using switch Statement

// Performs addition, subtraction, multiplication or division depending the input from user

# include <stdio.h>

int main() {

    char operator;
    double firstNumber,secondNumber;

    printf("Enter an operator (+, -, *,): ");
    scanf("%c", &operator);

    printf("Enter two operands: ");
    scanf("%lf %lf",&firstNumber, &secondNumber);

    switch(operator)
    {
        case '+':
            printf("%.1lf + %.1lf = %.1lf",firstNumber, secondNumber, firstNumber + secondNumber);
            break;

        case '-':
            printf("%.1lf - %.1lf = %.1lf",firstNumber, secondNumber, firstNumber - secondNumber);
            break;

        case '*':
            printf("%.1lf * %.1lf = %.1lf",firstNumber, secondNumber, firstNumber * secondNumber);
            break;

        case '/':
            printf("%.1lf / %.1lf = %.1lf",firstNumber, secondNumber, firstNumber / secondNumber);
            break;

        // operator doesn't match any case constant (+, -, *, /)
        default:
            printf("Error! operator is not correct");
    }
    
    return 0;
}

Output

Enter an operator (+, -, *,): *
Enter two operands: 1.5
4.5
1.5 * 4.5 = 6.8
Friday, 15 September 2017 09:08

Swap Numbers Using Temporary Variable

#include <stdio.h>
int main()
{
      double firstNumber, secondNumber, temporaryVariable;

      printf("Enter first number: ");
      scanf("%lf", &firstNumber);

      printf("Enter second number: ");
      scanf("%lf",&secondNumber);

      // Value of firstNumber is assigned to temporaryVariable
      temporaryVariable = firstNumber;

      // Value of secondNumber is assigned to firstNumber
      firstNumber = secondNumber;

      // Value of temporaryVariable (which contains the initial value of firstNumber) is assigned to secondNumber
      secondNumber = temporaryVariable;

      printf("\nAfter swapping, firstNumber = %.2lf\n", firstNumber);
      printf("After swapping, secondNumber = %.2lf", secondNumber);

      return 0;
}

Output

Enter first number: 1.20
Enter second number: 2.45

After swapping, firstNumber = 2.45
After swapping, secondNumber = 1.20

Program to Swap Number Without Using Temporary Variables

#include <stdio.h>
int main()
{
    double firstNumber, secondNumber;

    printf("Enter first number: ");
    scanf("%lf", &firstNumber);

    printf("Enter second number: ");
    scanf("%lf",&secondNumber);

    // Swapping process

    firstNumber = firstNumber - secondNumber;
    secondNumber = firstNumber + secondNumber;
    firstNumber = secondNumber - firstNumber;

    printf("\nAfter swapping, firstNumber = %.2lf\n", firstNumber);
    printf("After swapping, secondNumber = %.2lf", secondNumber);

    return 0;
}

Output

Enter first number: 10.25
Enter second number: -12.5

After swapping, firstNumber = -12.50
After swapping, secondNumber = 10.25
 
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